Prove that: 1/secA-tanA – 1/cosA = 1/cosA – 1/secA-tanA

Solution:

or, 1/secA-tanA + 1/ secA+tanA = 1/cosA + 1/cosA

or, (secA+tanA + secA-tanA)/(secA-tanA )(secA+tanA)= secA + secA

Or, 2secA/(sec२A-tan२A)=2secA

Therefore, 2secA=2secA proved